The hypotenuse of a triangle is 12 feet long. One leg is 6 feet long. What is the length of the other leg? Express youranswer in simplest radical form.ISubmitaINTLb1145

The formual for the pythagoras theorem with 'c' as hypotenuse, 'b' as base and 'a' as altitude is,
[tex]c^2=a^2+b^2[/tex]Substitute 12 for c and 6 for b to determine the length of other leg by using the pythagoras theoem.
[tex]\begin{gathered} (12)^2=a^2+(6)^2 \\ 144-36=a^2 \\ a^2=108 \\ a=\sqrt[]{108} \\ a=\sqrt[]{6\cdot6\cdot3} \\ =6\sqrt[]{3} \end{gathered}[/tex]The answer is,
[tex]6\sqrt[]{3}\text{ feet}[/tex]