Question

Find the equation of a line that passes through (1,11) and is parallel to the graph of y=2x+3 Write the equation in slope-intercept form, if possible.

Answer 1

Notice that the given line is in slope-intercept form, therefore its slope is 2.

Now, we know that parallel lines have the same slope, using the slope-point formula for the equation of a line we get:

$y-11=2(x-1)\text{.}$

Taking the above to its slope-intercept form we get:

$\begin{gathered} y-11=2x-2, \\ y-11+11=2x-2+11, \\ y=2x+9. \end{gathered}$

Answer:

$y=2x+9.$