Consider the general term,
[tex]a_n=2+6n[/tex]
Substitute 0, 1, 2, 3 to get the first 4 terms of the series,
[tex]2,8,14,20,\ldots\text{.}[/tex]
Consider that the difference between any two successive terms is constant at 6.
So this series will definitely form an arithmetic sequence.
So, it is a YES for the first box.
As already calculated the terms corresponding to n=0 is 2.
So the first term is 2.
Also the common difference is calculated by subtracting any term from its succeeding term,
[tex]\begin{gathered} d=a_{n+1}-a_n \\ d=2+6(n+1)-\mleft\lbrace2+6n\mright\rbrace \\ d=2+6n+6-2-6n \\ d=6 \end{gathered}[/tex]
Thus the common difference is 6.
