How does the graph of f(x) = 3√x-5 compare to the graph of g(x) = √x?

Answer:
Explanation:
Given the parent function:
[tex]f(x)=3\sqrt[]{x-5}[/tex]If f(x) is multiplied by 1/3, we have:
[tex]\begin{gathered} \frac{1}{3}f(x)=\frac{1}{3}\times3\sqrt[]{x-5} \\ =\sqrt[]{x-5} \end{gathered}[/tex]This means that f(x) has been shrunk vertically.
Next, we have:
[tex]\begin{gathered} \sqrt[]{(x-5)+5}=\sqrt[]{x} \\ g(x)=\sqrt[]{x} \end{gathered}[/tex]Thus:
[tex]g(x)=\frac{1}{3}f(x+5)[/tex]This is a vertical compression and horizontal translation left by 5 units.
Thus, the graph of f(x) is shrunk vertically and was moved to the left 5 units with re