Question

Mix & Match Directions: Match each scenario to its corresponding equation.

Answer 1

1.

In this case we have an initial value of 60 and it increases by 200 each year, so the best equation to represent this case is:

$y=60+200x$

2.

The original price is 55, and now the price is 4 times the initial price, so the best equation is:

$y=55(4^x)$

3.

The initial amount is 200, and it's multiplied by 0.5 (that is, half) each year, so the equation is:

$y=200(\frac{1}{2})^x$

4.

The initial cost is $50 and $5 more is added per line, so the best equation is:

$y=50+5x$

5.

The initial amount is $10 and it doubles (it's multiplied by 2) each year, so the equation is:

$y=10(2^x)$