QUESTION 17The roots of the equation 2x2 + 7x – 3 = 0 are02-7+ 734Ob7+734OcZ and 3Od- and -3

The roots of a qaudartic equation,
[tex]ax^2+bx+c=0[/tex]is,
[tex]x=\frac{-b\pm\sqrt[]{(b)^2-4ac}}{2a}[/tex]The value of a, b and c for the given equation is,
a = 2
b = 7, and
c = -3.
Determine the roots of the quadratic equation.
[tex]\begin{gathered} x=\frac{-7\pm\sqrt[]{(7)^2-4\cdot2\cdot(-3)}}{2\cdot2} \\ =\frac{-7\pm\sqrt[]{49+24}}{4} \\ =\frac{-7\pm\sqrt[]{73}}{4} \end{gathered}[/tex]So option A is correct answer.