Question

(x^2÷x)^2(-4)^2-x x=5

Answer 1

Given:

$\begin{gathered} (\frac{x^2}{x})^2(-4)^2-x \\ \\ x=5 \end{gathered}$

To solve the expression when x = 5, substitute x for 5 and evaluate.

We have:

$\begin{gathered} (\frac{5^2}{5})^2(-4)^2-5 \\ \\ =(\frac{25}{5})^2(16)-5 \end{gathered}$

Solving further:

$\begin{gathered} =(5)^2(16)-5 \\ \end{gathered}$$undefined$