Question

A 10 kg box is being pushed to the right with 10.0 N of force while experiencing 8.0 N of friction force. What is the sum of all of the forces on the box?

Answer 1

Given information:

Applied force,

$F=10.0\text{ N}$

Friction force,

$f=8.0\text{ N}$

Schematic diagram:

The net force acting on the box is given as,

$F_{net}=F-f$

Substituting all known values,

$\begin{gathered} F_{net}=(10.0\text{ N})-(8.0\text{ N}) \\ =2.0\text{ N} \end{gathered}$

Therefore, the sum of all of the forces on the box is 2.0 N.