We have:
[11: 11, 6, 2, 1] there are 4! = 1 x 2 x 3 x 4 = 24, then sequencial coalitions is:
[tex]\begin{gathered} \lbrack P1,P2,P3,P4\rbrack,\lbrack P2,\bar{P1},P3,P4\rbrack,\lbrack P3,\bar{P1},P2,P4\rbrack,\lbrack P4,\bar{P1},P2,P3\rbrack^{} \\ \lbrack P1,P2,P4,P3\rbrack,\lbrack P2,\bar{P1},P4,P3\rbrack^{},\lbrack P3,\bar{P1},P4,P2\rbrack,\lbrack P4,\bar{P1},P3,P2\rbrack^{} \\ \lbrack P1,P3,P2,P4\rbrack,\lbrack P2,P3,\bar{P1},P4\rbrack^{},\lbrack P3,P2,\bar{P1},P4\rbrack,\lbrack P4,P2,\bar{P1,}P3\rbrack^{} \\ \lbrack P1,P3,P4,P2\rbrack,\lbrack P2,P3,P4,P1\rbrack^{},\lbrack P3,P2,P4,P1\rbrack,\lbrack P4,P2,P3,P1\rbrack^{} \\ \lbrack P1,P4,P2,P3\rbrack,\lbrack P2,P4,\bar{P1},P3\rbrack^{},\lbrack P3,P4,\bar{P1,}P2\rbrack,\lbrack P4,P3,\bar{P1},P2\rbrack^{} \\ \lbrack P1,P4,P3,P2\rbrack,\lbrack P2,P4,P3,P1\rbrack,\lbrack P3,P4,P2,P1\rbrack,\lbrack P4,P3,P2,P1\rbrack \end{gathered}[/tex]the shapley shubik power distribution:
[tex]P1=\frac{12}{24}=\frac{1}{2}[/tex][tex]undefined[/tex]