Question

What is the range of the function f (2) = 3x2 + 4.c when the domain is {-1, 0, -3}?hint: domain represents x values, range represents y values points have x and y values...

Answer 1

Given the following function and its domain:

$\begin{gathered} f(x)=3x^2+4x \\ Domf=\mleft\lbrace-1,0,-3\mright\rbrace \end{gathered}$

we can find the range by evaluating each member of the domain on the function:

$\begin{gathered} f(-1)=3(-1)^2+4(-1)=3-4=-1 \\ f(0)=3(0)^2+4(0)=0 \\ f(-3)=3(-3)^2+4(-3)=27-12=15 \end{gathered}$

therefore, the range of the function f(x) is {-1,0,15}