Solve each equation first and then choose the appropiate statement.
Equation 1
[tex]|5x-6|=-41[/tex]
Since the absolute value of a number is always greater than 0 and -41<0, then this equation has no solutions.
Equation 2
[tex]\begin{gathered} |7x+13|=27 \\ \Rightarrow7x+13=\pm27 \\ \Rightarrow7x=\pm27-13 \\ \Rightarrow x=\frac{\pm27-13}{7} \\ \Rightarrow x_1=\frac{27-13}{7}=\frac{14}{7}=2 \\ \Rightarrow x_2=\frac{-27-13}{7}=\frac{-40}{7} \\ \therefore x_1=2,x_2=-\frac{40}{7} \end{gathered}[/tex]
We can see that Equation 1 has 0 solutions and Equation 2 has 2 solutions.
Therefore, equation 2 has more solutions than equation 1.