Let's make a diagram to represent this situation
As you can observe in the diagram, we have a right triangle, and we know one leg and one acute angle. So, in order to find the height y, we have to use the tangent function which relates the opposite leg and the adjacent leg.
[tex]\begin{gathered} \tan 30=\frac{75}{y} \\ y=\frac{75}{\tan 30} \\ y\approx129.9 \end{gathered}[/tex]To find the diagonal distance, we use the sine function which relates the opposite leg and the hypothenuse.
[tex]\begin{gathered} \sin 30=\frac{75}{h} \\ h=\frac{75}{\sin 30} \\ h=\frac{75}{0.5}=150 \end{gathered}[/tex]