Using the equation of slope
[tex]\text{slope =}\frac{y_2-y_1}{x_2-x_1}[/tex]From the question,
slope =2/3
x₁ =3 y₁=-3 x₂= k y₂=5
substitute the values into the formula
[tex]\frac{2}{3}=\frac{5+3}{k-3}[/tex]cross-multiply
2(k-3) = 3(5+3)
2k - 6 = 3(8)
2k - 6 = 24
Add 6 to both-side of the equation
2k = 24 + 6
2k = 30
Divide both-side of the equation by 2
k = 15
The answer is 15
