We have the circle equation
[tex](x-6)^2+(y+3)^2=r^2[/tex]We will find the radius r by substituting the given point, which belongs to the circle, that is,
[tex](4-6)^2+(1+3)^2=r^2[/tex]which gives
[tex]\begin{gathered} (-2)^2+4^2=r^2 \\ 4+16=r^2 \\ 20=r^2 \end{gathered}[/tex]Then, the circle equation is
[tex](x-6)^2+(y+3)^2=20[/tex]