Given:
The probability of growing oif healthy plant is p = 0.65 (65%).
The number of trials is n = 7.
Explanation:
The probability for plant does not grow is,
[tex]\begin{gathered} q=1-0.65 \\ =0.35 \end{gathered}[/tex]
Probability for exactly 1 plant doesn't grow also means that 6 plants grow healthy.
The formula of binomial probability is,
[tex]^nC_xp^xq^{n-x}[/tex]
The value of x for this case is 6.
Substitute the values in the formula to detemine the probabilit for 6 plant grow healthy or 1 plant doesn't grow.
[tex]\begin{gathered} ^7C_6(0.65)^6(0.35)^1=\frac{7!}{6!\cdot1!}\cdot(0.07541889)\cdot(0.35) \\ =0.18477 \\ \approx0.1848 \end{gathered}[/tex]
Answer: 0.1848
