Question

solve by square root$(3x - 2) ^{2} = - 12$

Answer 1

Solve by square root;

$(3x-2)^2=-12$

We start by taking the square root of both sides, and we'll have;

$\sqrt[]{(3x-2)^2}=\pm\sqrt[]{-12}$

Note that the square root sign cancels out the square sign on the left side.

$3x-2=\pm\sqrt[]{-12}$

The square root of negative 12 can be splitup into the following;

$undefined$