Given:
[tex](2+i)(-3+5i)[/tex]
apply the complex arithmetic rule,
[tex](a+bi)(c+di)=(ac-bd)+(ad+bc)i[/tex][tex]\begin{gathered} a=2 \\ b=1 \\ c=-3 \\ d=5 \end{gathered}[/tex]
thus,
[tex]\begin{gathered} (2(-3)-1\cdot5)+(2\cdot5+1\cdot(-3))i \\ -11+7i \end{gathered}[/tex]
