Question

Bruce had a pet worm that fell into a well. the well is 37 feet deep. each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet. how many days will it take for the worm to get out of the well?

Answer 1

The depth of the well is d = 37 feet.

The worm climb up height of 7 feet each day and slides down 2 feet down. So worms climbs by height of,

$\begin{gathered} h=7-2 \\ =5 \end{gathered}$

So worm climb 5 feet up on the well.

Determine the number of days to climb up to the well.

$\begin{gathered} T=\frac{37}{5} \\ =7\frac{2}{5} \end{gathered}$

So 7 days require to climb a height of 35 feet for climb of remaining 2 feet one more day is required.

Thus, worm take 8 days to climb the height of 37 feet.