cost price selling price(please show calculations)Both images is one question


We have the cost function in function of the number of hamburgers as:C
[tex]C(h)=4000+8h[/tex]1.1) We have to represent the income I.
It will be equal to the number of hamburgers times the price of each hamburguer ($20).
Then, we can write it as:
[tex]I(h)=20h[/tex]1.2) We have to complete the table for each production level.
We can use the functions to calculate for each level.
We start with the expenses:
[tex]\begin{gathered} C(0)=4000+8(0)=4000+0=4000 \\ C(200)=4000+8(200)=4000+1600=5600 \\ C(400)=4000+8(400)=4000+3200=7200 \\ C(600)=4000+8(600)=4000+4800=8800 \\ C(800)=4000+8(800)=4000+6400=10400 \\ C(1000)=4000+8(1000)=4000+8000=12000 \end{gathered}[/tex]We can now calculate the income I(h) as:
[tex]\begin{gathered} I(0)=20(0)=0 \\ I(200)=20(200)=4000 \\ I(400)=20(400)=8000 \\ I(600)=20(600)=12000 \\ I(800)=20(800)=16000 \\ I(1000)=20(1000)=20000 \end{gathered}[/tex]We can then complete the table as:
We now have to graph both functions.
We can use the horizontal axis for h and the vertical axis for C and I and obtain:
1.4) From the graph we know that the amount of hamburguers he need to sell to break even is between 300 and 400, where C(h) = I(h).
We can use the equations to find the exact value:
[tex]\begin{gathered} C(h)=I(h) \\ 4000+8h=20h \\ 4000=(20-8)h \\ 4000=12h \\ h=\frac{4000}{12} \\ h\approx334 \end{gathered}[/tex]1.5) We can calculate how much he loss when h = 200 as the difference between the income and the cost for that level.
[tex]\begin{gathered} P(200)=I(200)-C(200) \\ P(200)=4000-5600 \\ P(200)=-1600 \end{gathered}[/tex]He loss $1600 if he sells only 200 hamburguers.
1.6) We have to calculate h for I(h) = 15000:
[tex]\begin{gathered} I(h)=15000 \\ 20h=15000 \\ h=\frac{15000}{20} \\ h=1250 \end{gathered}[/tex]The number of hamburguers is 1250.
1.7) The profit for 1000 hamburguers can be calculated as:
[tex]\begin{gathered} I(1000)-C(1000) \\ 20000-12000 \\ 8000 \end{gathered}[/tex]The maximum profit would be $8000.
Answer:
1.1) I(h) = 20h
1.2) Given in the answer
1.4) 334 hamburguers
1.5) He will loss R 1600
1.6) 1250 hamburguers
1.7) R 8000