Question

20) A gain silo is constructed as two cones and a cylinder. The measurements are represented by the figure. What is the approximate volume of the grain silo? Hint: Volume of a cone = 1/3 tir^2h and Volume of a cylinder = ter^2h OR Volume of silo = tr^2h + 2(1/3 ter^2h)

Answer 1

Answer:

1046.66 ft³

Explanation:

The volume of the silo can be calculated as:

$\text{Volume of Silo = }\pi r^2h_1+2(\frac{1}{3}\pi r^2h_2)$

Where π is approximately 3.14, r is the radius of the silo, h1 is the height of the cylinder and h2 is the height of the cone.

So, replacing π by 3.14, r by 5 ft, h1 by 10 ft, and h2 by 5ft, we get that the volume is equal to:

$\begin{gathered} \text{Volume of Silo = (3.14)(5}^2)(10)+2(\frac{1}{3})(3.14)(5^2)(5) \\ \text{Volume of Silo = (3.14)(25}^{})(10)+2(\frac{1}{3})(3.14)(25)(5) \\ \text{Volume of Silo = 785 + 261.66} \\ \text{Volume of Silo = 1046.66} \end{gathered}$

Therefore, the volume of the silo is 1046.66 ft³