Respuesta :

Solution

Note: Law of Indices

[tex]\begin{gathered} a^m\times a^n=a^{m+n} \\ and \\ a^0=1 \end{gathered}[/tex]

To solve the problem

[tex]\begin{gathered} a^2\times a^{-3}\times a=a^2\times a^{-3}\times a^1 \\ a^2\times a^{-3}\times a=a^{2-3+1} \\ a^2\times a^{-3}\times a=a^0 \\ a^2\times a^{-3}\times a=1 \end{gathered}[/tex]

Therefore, the answer is

[tex]1[/tex]

RELAXING NOICE
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