Question

What is the solution to the equation below? 2х 、 x -2 O A. X= 3 O B. x=6 C. X= 4 D. X= 5

Answer 1

The given equation is

$\frac{\sqrt[]{2x}}{\sqrt[]{x-2}}=2$

We will square both sides to cancel the roots

$\frac{(\sqrt[]{2x})^2}{(\sqrt[]{x-2)^2}}=(2)^2$

Power 2 will cancel the square roots on the left side

$\frac{2x}{x-2}=4$

By using cross multiplication