Question

Use the quadratic formula to solve for the zero(s) of the equation y = -0.125x2 + 0.35x + 0.75. Round to the nearest hundredth.

Answer 1

Given:

There is a expression given as

$-0.125x^2+0.35x+0.75=y$

Required:

We need to find the Zeros of given expression

Explanation:

$\begin{gathered} -0.125x^2+0.35x+0.75=0 \\ -125x^2+350x+750=0 \end{gathered}$

now compare the given equation with

$ax^2+bx+c=0$

a=-125

b=350

c=750

now by using the quadratic formula

$x_1,x_2=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-350\pm\sqrt{350^2-4\left(-125\right)\cdot\:750}}{2\left(-125\right)}$

after simplify

$undefined$