Equation of line:
y = mx + c
we need to find the slope of the line using any two points:
using points (-3, 3) and (3, 1)
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} x_1=-3,y_1=3,x_2=3,y_2\text{ = 1} \\ \text{slope = }\frac{1-3}{3-(-3)}=\frac{-2}{3+3} \\ \text{slope = }\frac{-2}{6}=\text{ -1/3} \end{gathered}[/tex]c = y -intercept
This is the point the line crosses the y axis. The line cross y axis at y = 2
c = 2
The equation of line becomes:
[tex]y\text{ = }\frac{-1}{3}x\text{ + 2 (option 3)}[/tex]