Respuesta :

[tex]y\text{ = }\frac{-1}{3}x\text{ + 2 (option 3)}[/tex]Explanation:

Equation of line:

y = mx + c

we need to find the slope of the line using any two points:

using points (-3, 3) and (3, 1)

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} x_1=-3,y_1=3,x_2=3,y_2\text{ = 1} \\ \text{slope = }\frac{1-3}{3-(-3)}=\frac{-2}{3+3} \\ \text{slope = }\frac{-2}{6}=\text{ -1/3} \end{gathered}[/tex]

c = y -intercept

This is the point the line crosses the y axis. The line cross y axis at y = 2

c = 2

The equation of line becomes:

[tex]y\text{ = }\frac{-1}{3}x\text{ + 2 (option 3)}[/tex]

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