Given: A logarithmic function
[tex]g(x)=\log_4(x+2)[/tex]
Required: To graph the given function with asymptote and give the domain and range of the function.
Explanation: To graph, the given function draw a table of g(x) and x as follows
Now plotting these points on a graph gives
Now the vertical asymptote can be found by setting argument (x+2) equal to zero.
Which gives x=-2 as an asymptote of the given function.
Now for the domain and range of the function
[tex]Domain:\text{ }(-2,\infty),\lbrace x:x>-2\rbrace[/tex][tex]Range:(-\infty,\infty),\lbrace y:y\in\Re\rbrace[/tex]
Where y=g(x)
Final Answer: Vertical Asymptote occurs at x = -2
[tex]\begin{equation*} Domain:\text{ }(-2,\infty),\lbrace x:x>-2\rbrace \end{equation*}[/tex][tex]Range:(-\infty,\infty),\lbrace y:y\in\Re\rbrace[/tex]