Getting a hit in each bat gives a probability of 0.46
Therefore, probability of not getting a hit:
[tex]1-0.46=0.54[/tex]We have a question on binomial probability where.
p = probability of occurence = 0.46
q = probability of non occurence = 0.54
n = sample space
r = no of expected outcome
Therefore, the probability of getting the hit in her first batting:
[tex]\begin{gathered} P=p^rq^{n-r} \\ P=0.46^1\times0.54^3=0.0724 \end{gathered}[/tex]Probability that she gets a hit only in her first bat is 0.0724