Answer:
[tex]-\frac{4}{r^8}[/tex]
Explanation:
Given the expression:
[tex]-4r^{-8}s^0[/tex]
First, any number (except 0) raised to the power of 0 is 1. Thus:
[tex]-4r^{-8}s^0=-4r^{-8}\times1=-4r^{-8}[/tex]
Next, apply the negative index law of indices:
[tex]a^{-n}=\frac{1}{a^n}[/tex]
Therefore:
[tex]\begin{gathered} -4r^{-8}=-4\times r^{-8} \\ =-4\times\frac{1}{r^8} \\ =-\frac{4}{r^8} \end{gathered}[/tex]
The given expression written using positive exponents only is:
[tex]-\frac{4}{r^8}[/tex]
