Answer: First Option is correct i.e. [tex]^9C_3(0.5)^3(0.5)^6[/tex]
Step-by-step explanation:
Since we have given that
Number of times Aron flips a penny = 9 times
Number of heads getting by him exactly = 3
Probability of getting a head (success) is given by
[tex]\frac{1}{2}[/tex]
Probability of getting a tail ( failure ) is given by
[tex]\frac{1}{2}[/tex]
So, We need to find the probability of getting exactly 3 heads:
[tex]P(x=3)=^9C_3(\frac{1}{2})^3\times \frac{1}{2}^6\\\\P(x=3)=^9C_3(0.5)^3\times (0.5)^6\\\\P(x=3)=\frac{9!}{3!\tiems 6!}\times (0.5)^9\\\\P(x=3)=0.16[/tex]
Hence, First Option is correct i.e. [tex]^9C_3(0.5)^3(0.5)^6[/tex]
