Question

Find the equation of the line described, in standard form containing (3,5) and a horizontal m = 0.

Answer 1

Given a point (3, 5) and a slope = 0, we can solve its equation using the Point-Slope form formula.

$y-y_1=m(x-x_1)$

From this, let's replace y₁ with 5, x₁ with 3, and m = 0.

$\begin{gathered} y-5=0(x-3) \\ y-5=0 \\ y=5 \end{gathered}$

In standard form, the equation is 0x + y = 5 or y = 5.

Below is the graph of this line.