Question

Calculate the magnitude of the electric field strength at a point in a field where an electronn experiences a force with a magnitude of 3.9 * 10^(-16) N.

Answer 1

ANSWER

$2,434.46N\/C$

EXPLANATION

To find the strength of the electric field, apply the formula below:

$E=\frac{F}{q}$

where F = electric force, q = charge of the electron

Hence, the strength of the electric field is:

$\begin{gathered} E=\frac{3.9\cdot10^{-16}}{1.602\cdot10^{-19}} \\ E=2,434.46N\/C \end{gathered}$

That is the answer.