Question

2.Cowboys kicker Brett Maher kicks the ball off at 25 m/s at an angle of 60° determine the time of flight

Answer 1

Given data:

* The initial velocity of the ball is 25 m/s.

* The angle of the initial velocity with the horizontal is 60 degree.

* The final vertical velocity of the ball at the maximum height is 0 m/s.

Solution:

By the kinematics equation, the time taken by the projectile to reach the maximum height is,

$v^{}-u=-gt$

where v is the final vertical velocity at the maximum, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time taken to reach the maximum height,

$\begin{gathered} 0-25\sin (60^{\circ})=-9.8\times t \\ -21.65=-9.8t \\ t=\frac{-21.65}{-9.8} \\ t=2.21\text{ s} \end{gathered}$

Thus, the time of flight of the ball is,

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