Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.1Passing through (6. - 5) and perpendicular to the line whose equation is y= 2x+5Write an equation for the line in point-slope form.(Simplify your answer. Use integers or fractions for any numbers in the equation)Write an equation for the line in slope-intercept form.(Simplify your answer. Use integers or fractions for any numbers in the equation)anand

Use the given conditions to write an equation for the line in pointslope form and in slopeintercept form1Passing through 6 5 and perpendicular to the line whose class=

Respuesta :

Given:

The line is perpendicular to the line whose equation is

[tex]y\text{ = }\frac{1}{4}x\text{ + 5}[/tex]

It passes through the point (6, -5)

A line with a slope (m) is perpendicular with another line with a slope (m*) if:

[tex]m\text{ }\times m^{\cdot}\text{ = -1}[/tex]

The slope of the line would thus be:

[tex]\begin{gathered} \text{slope = }\frac{-1}{\frac{1}{4}} \\ =\text{ -4} \end{gathered}[/tex]

In point-slope form:

[tex]\begin{gathered} y\text{ - (-5) = -4(x-6)} \\ y\text{ + 5 = -4(x -6)} \end{gathered}[/tex]

In slope-intercept form:

[tex]\begin{gathered} y+\text{ 5 = -4(x-6)} \\ y\text{ + 5 = -4x + 24} \\ y\text{ = -4x + 24 - 5} \\ y\text{ = -4x + 19} \end{gathered}[/tex]

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