SOLUTION:
Case: Standard deviation
Given:
Mean(µ): 33.56 mph
Standard deviation(σ): 3.35 mph
Hence, the value of standard deviation, away from the mean is calculated by th
Calculation:
[tex]\begin{gathered} z=\frac{X-\mu}{\frac{\eta}{\sqrt{N}}} \\ z=\frac{30-33.56}{\frac{3.35}{\sqrt{100}}} \\ z=-10.62 \end{gathered}[/tex]Final answer:
A) There are about -10.62 values from the mean as standard deviation