Respuesta :

First, let us evaluate the function:

[tex]\frac{2(x+h)^2-x+h-2x^2+x}{h}[/tex]

Simplify:

[tex]\begin{gathered} \frac{2(x^2+2xh+h^2)-(x+h)-2x^2+x}{h} \\ \frac{2x^2+4xh+2h^2-x-h-2x^2+x}{h} \end{gathered}[/tex]

Solve like terms:

[tex]\frac{4xh+2h^2-h}{h}[/tex]

Factorize h from the numerator:

4xh +2h²-h = h(4x+2h-1)

Then

[tex]\begin{gathered} \frac{h\mleft(4x+2h-1\mright)}{h} \\ =4x+2h-1 \end{gathered}[/tex]

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