parallel lines have the same slopes. Therefore,
[tex]m_1=m_2_{}_{}_{}[/tex][tex]m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{7-4}{6-3}=\frac{3}{3}=1[/tex][tex]m_2=1[/tex]Y can be found below
[tex]\begin{gathered} 1=\frac{y-8}{6-2} \\ 1=\frac{y-8}{4} \\ 4=y-8 \\ y=4+8 \\ y=12 \end{gathered}[/tex]