Question

evaluate x^0 y^-4 for x = 2 and y = 3.

Answer 1

We have to evaluate the expression:

$x^0y^{-4}=1\cdot y^{-4}=\frac{1}{y^4}$

for x=2 and y=3.

The value of x is elevated to the exponent 0 so the value of x^0 is always 1 for any value of x.

Then, we replace y with 3 and calculate:

$x^0y^{-4}=\frac{1}{y^4}=\frac{1}{3^4}=\frac{1}{81}$

Answer: the value of the expression for x=2 and y=3 is 1/81.