Question

Graph the line that has a slope of 1/5 and includes the point (0,1).

Answer 1

Given:

$\text{Slope(m)}=\frac{1}{5}\text{ ; Point (0,1)}$

Equation of line is

$y-y_1=m(x-x_1)$$\begin{gathered} y-1=\frac{1}{5}(x-0) \\ 5y-5=x \\ x-5y+5=0 \end{gathered}$

Equation can be written as

$y=\frac{x+5}{5}$

x=-10,

$\begin{gathered} y=\frac{-10+5}{5} \\ y=\frac{-5}{5} \\ y=-1 \end{gathered}$

x=-5,

$\begin{gathered} y=\frac{-5+5}{5} \\ y=0 \end{gathered}$

x=0

$\begin{gathered} y=\frac{5}{5} \\ y=1 \end{gathered}$

x=5

$\begin{gathered} y=\frac{5+5}{5} \\ y=2 \end{gathered}$

x=10

$\begin{gathered} y=\frac{10+5}{2} \\ y=3 \end{gathered}$

Plot the points on the graph

$(-10,-1),(-5,0),(0,1),(5,2),(10,3)$