Given exprression is 12x>3(5x-2)-15.
Opening the brackets implies,
[tex]\begin{gathered} 12x>15x-6-15 \\ 12x>15x-21 \end{gathered}[/tex]
Reaaranging the expression implies,
[tex]\begin{gathered} 21>3x \\ x<7 \end{gathered}[/tex]
Therefore, the solution is x<7.
Expressit in real line implies,
