Question

A coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing a tail and then rolling a number greater than 2. The probability of tossing a tail and then rolling a number greater than 2 is ___

Answer 1

Given that:

- A coin is tossed.

- An eight-sided dice is rolled. This is numbered 1 through 8.

1. By analyzing the information provided in the exercise, you can identify that tossing a coin and getting a tail; and rolling a dice getting a number greater than 2 are Independent Events.

2. Knowing that the probability of occurring two independent events together is equal to the product of their probabilities:

• Let be "A": Tossing a tail.

,

• Let be "B": Rolling a number greater than 2.

3. Then, the formula is:

$P(A\cap B)=P(A)\cdot P(B)$

4. You need to find:

$\begin{gathered} P(A) \\ P(B) \end{gathered}$

You can determine that:

$P(A)=\frac{1}{2}$

Because the coin only has two faces.

And:

$P(B)=\frac{6}{8}=\frac{3}{4}$

Because the dice has 8 sides and you need to find a number greater than 2. This gives you a set of 6 possible values:

$\lbrace3,4,5,6,7,8\rbrace$

Finally, substituting values into the formula and evaluating, you get:

$P(A\cap B)=\frac{1}{2}\cdot\frac{3}{4}=\frac{1\cdot3}{2\cdot4}=\frac{3}{8}$

Hence, the answer is:

The probability of tossing a tail and then rolling a number greater than 2 is:

$P(A\cap B)=\frac{3}{8}$