[tex]\begin{gathered} Let^{\prime}s1st\text{ side is x.} \\ 2nd\text{ side is x+8} \\ 3\text{rd side is 4x.} \\ \text{Perimeter}=1st+2nd+3rd \\ 26=x+x+8+4x \\ 6x=26-8 \\ x=3 \\ So,\text{ the length of third side is} \\ 3rd=4x \\ 3rd=4\times3 \\ 3rd=12\text{ meter.} \end{gathered}[/tex]