Question

Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.

Answer 1

5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5

Answer 2

x intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0


so find x and y intercept

yintercept, x=0
5y=10
y=2
yint is (0,2)

xint, y=0
2x=10
x=5
xint is (5,0)
double


yint is (0,4) and yint is (10,0)

ok, so we do
y=mx+b
m=slope
b=yint
givenyint=4

y=mx+4
when x=10, y=00 because we got (10,0)
0=10m+4
miinus 4 both sides
-4=10m
divide oth sides by 10
-2/5=m

the equation is y=-2/5x+4 or
2/5x+y=4
2x+5y=20