Let's copy the equation:
[tex]8x-2(x+1)=7x+8[/tex]Now, it is best for us to get rid of the parenthesis, which can be done by applying the distributive property:
[tex]\begin{gathered} 8x-2(x+1)=7x+8 \\ 8x-2x-2=7x+8 \\ 6x-2=7x+8 \end{gathered}[/tex]Now, let's put the terms with "x" to the left and the terms without "x" to the right:
[tex]\begin{gathered} 6x-7x=8+2 \\ -x=10 \end{gathered}[/tex]Now, we can pass the sign by changing it in both sides:
[tex]x=-10[/tex]Thus, the solution is x = -10, which is alternative D.