Given:
AB=40 mm
BC=20 mm
AC=27 mm
The objective is to dilate triangle ABD with a scale factor of 2, using A as the centre.
Since, if A is used as center, then the remaining sides will get reduced by a factor of 2.
If AB=40mm,
[tex]\begin{gathered} AB^{\prime}=\frac{AB}{Scalefactor} \\ AB^{\prime}=\frac{40}{2} \\ AB^{\prime}=20 \end{gathered}[/tex]
Similarly if BC=20 mm
[tex]\begin{gathered} B^{\prime}C^{\prime}=\frac{BC}{Scale\text{ factor}} \\ B^{\prime}C^{\prime}=\frac{20}{2} \\ B^{\prime}C^{\prime}=10\text{ } \end{gathered}[/tex]
And if AC=27 mm
[tex]\begin{gathered} AC^{\prime}=\frac{AC}{Scale\text{ factor}} \\ AC^{\prime}=\frac{27}{2} \\ AC^{\prime}=13.5 \end{gathered}[/tex]
If we construct the dilated triangle AB'C',
Hence, the required dilated triangle AB'C' has been obtained.
