I just need the answer you dont have to deeply explainA. 4 to the square root of 2B. 3 to the square root of 2C. 2 to the square root of 2 D 8

Given:
Hypotenuse=x, Adjacent side=4, and angle is 45 degrees.
Consider the cos formula.
[tex]\cos \theta=\frac{\text{Adjacent side}}{\text{hypotenuse}}[/tex][tex]\text{ Substitute hypotenuse= x, adjacent side =4, and }\theta=45^o,\text{ we get}[/tex][tex]\cos 45^o=\frac{4}{x}[/tex]Using the cross-product method, we get
[tex]x=\frac{4}{\cos 45^o}[/tex][tex]\text{Use }\cos 45^o=\frac{1}{\sqrt[]{2}}[/tex][tex]x=\frac{4}{\frac{1}{\sqrt[]{2}}}=4\times\frac{\sqrt[]{2}}{1}=4\sqrt[]{2}[/tex]The length of x is
[tex]4\sqrt[]{2}[/tex]
Option A is correct.