Question

Identify the function that vertically stretches f(x) = -4x^3 + 1 by a factor of 2 and shifts it 7 units left.

Answer 1

Answer:

$h(x)=-8(x+7)^3+2$

Explanation:

Given the function:

$f\mleft(x\mright)=-4x^3+1$

Stretching f(x) vertically by a factor of 2 gives:

$2f(x)=2(-4x^3+1)$

Next, shifting it by 7 units left:

$\begin{gathered} 2f(x+7)=2(-4(x+7)^3+1) \\ h(x)=-8(x+7)^3+2 \end{gathered}$

The second option is correct.