Which of the following is the equation in 2 = 3x + 1 written in exponential form?

Given
[tex]\ln 2=3x+1[/tex]
Procedure
The natural log, or ln, is the inverse of e.
[tex]\begin{gathered} e^{\ln 2}=e^{3x+1} \\ 2=e^{3x+1} \end{gathered}[/tex]The answer would be option B. 2 = e^(3x+1)