ANSWER
[tex]y=-4[/tex]EXPLANATION
We want to find the y-intercept of the equation in question.
The general form of a quadratic equation is:
[tex]y=ax^2+bx+c[/tex]A quadratic equation with a = 5, b = 8 and c = -4 can therefore be written as:
[tex]y=5x^2+8x-4[/tex]The y-intercept is the value of y when x = 0.
Therefore, the y-intercept is:
[tex]\begin{gathered} y=5(0)^2+8(0)-4 \\ y=0+0-4 \\ y=-4 \end{gathered}[/tex]