Answer:
x = -1 and x = 2/3
Explanation:
The equation given is a quadratic equation.
Therefore, to solve for x we use the quadratic formula.
The quadratic formula says that if we have an equation of the form
[tex]ax^2+bx+c=0[/tex]Then the values of x (solutions) are given by
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Now in our case, the equation we have is
[tex]3x^2+x-2=0[/tex]which tells us that a = 3, b = 1, and c = -2; therefore, quadratic formula gives
[tex]x=\frac{-1\pm\sqrt{(1)^2-4(3)(-2)}}{2(3)}[/tex]which we simplify a bit to get
[tex]x=\frac{-1\pm\sqrt{1+24}}{6}[/tex][tex]\Rightarrow x=\frac{-1\pm5}{6}[/tex]which gives us two solutions:
[tex]x=\frac{-1-5}{6}=-1[/tex][tex]x=\frac{-1+5}{6}=\frac{2}{3}[/tex]Hence, the two solutions to the quadratic equation are x = -1 and x = 2/3.