Respuesta :

Answer:

x = -1 and x = 2/3

Explanation:

The equation given is a quadratic equation.

Therefore, to solve for x we use the quadratic formula.

The quadratic formula says that if we have an equation of the form

[tex]ax^2+bx+c=0[/tex]

Then the values of x (solutions) are given by

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Now in our case, the equation we have is

[tex]3x^2+x-2=0[/tex]

which tells us that a = 3, b = 1, and c = -2; therefore, quadratic formula gives

[tex]x=\frac{-1\pm\sqrt{(1)^2-4(3)(-2)}}{2(3)}[/tex]

which we simplify a bit to get

[tex]x=\frac{-1\pm\sqrt{1+24}}{6}[/tex][tex]\Rightarrow x=\frac{-1\pm5}{6}[/tex]

which gives us two solutions:

[tex]x=\frac{-1-5}{6}=-1[/tex][tex]x=\frac{-1+5}{6}=\frac{2}{3}[/tex]

Hence, the two solutions to the quadratic equation are x = -1 and x = 2/3.

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