The Solution:
Given the table below:
We are required to determine the value of the letters A, B, C, and D.
[tex]\begin{gathered} 2\text{ tickets = \$8} \\ \text{ This means} \\ 1\text{ ticket =}\frac{8}{2}=\text{ \$4} \end{gathered}[/tex]
To find A (cost of 3 tickets)
[tex]A=3\times4=\text{ \$12}[/tex]
To find B (cost of 7 tickets)
[tex]B=7\times4=\text{ \$28}[/tex]
To find C (number of tickets that cost $20)
[tex]C=\frac{20}{4}=5\text{ tickets}[/tex]
To find D (number of tickets that cost $40)
[tex]D=\frac{40}{4}=10\text{ tickets}[/tex]
Therefore, the correct answers are:
A=12, B=28, C=5 and D=10