(a) What was the impact speed when the lander touched the ground.
The impact speed is given by
[tex]v=\sqrt[]{2gh}[/tex]Where g is the acceleration of gravity on the moon and h is the distance from the ground.
For the given case,
g = 1.62 m/s^2 = 5.31 ft/s^2
h = 4.3 ft
[tex]v=\sqrt[]{2gh}=\sqrt[]{2\cdot5.31\cdot4.3}=6.76\; \frac{ft}{s}[/tex]The impact speed of the lander is 6.76 ft/s
(b) How long did it take for the lander to drop the last 4.3ft
The time is given by
[tex]\begin{gathered} y=\frac{1}{2}gt^2 \\ 4.3=\frac{1}{2}\cdot5.31\cdot t^2 \\ t^2=\frac{2\cdot4.3}{5.31} \\ t^2=1.6196 \\ t^{}=\sqrt{1.6196} \\ t=1.27\; s \end{gathered}[/tex]Therefore, it takes 1.27 s for the lander to drop the last 4.3 ft